Showing Value Letter With IF

This time we will try to program C + + to show the value of letters of numbers entered by the user. So for example user input 85 numbers then it will display the letter A. Problem selengkapkanya are as follows:

By using the IF statement, create a program to display the letter from the value entered by the user, with sebegai following provisions:
• If the value is greater than 80, then the value of letter = A
• If the value is greater than 75, then the value of letter = B
• If a value greater than 65, then the value of letter = C
• If the value is greater than 45, then the value of letter = D
• If the value is less than or equal to 45, then the value of letter = E
• If the input value is greater than 100 or less than 0, it will display the message "wrong input".
To make the program C + + displays the value of letters as a matter of the above, we can use the IF statement. The following source code C + + program to display the value of these letters:

01  # include <iostream> 02  # include <conio.h> 03 04  void main () 05  { 06  court <<"Program Point Value" <<endl; 07  int bil; 08  court <<"Enter the value number:"; 09  cin>> bil; 10  if (bil> 100 | | bil <0) 11  court <<"Input wrong"; 12  else if (bil> 80) 13  court <<"The value of letter = A"; 14  else if (bil> 75) 15  court <<"The value of letter = B"; 16  else if (bil> 65) 17  court <<"The value of letter = C"; 18  else if (bil> 45) 19  court <<"The value of letter = D"; 20  else 21  court <<"The value of letter = E"; 22  getch (); 23  }

Explanation of the program displays the value of the letter:
In accordance with the provisions in question, then we must ensure that if the input is above 100 or below 0 will display the message "Input wrong", therefore first tested whether the input above 100 or below 0. Further testing of the new input values ​​to determine the value of the letters according to the provisions on the matter.